A) a free 5' OH.
B) DNA primers.
C) RNA primers.
D) telomerase.
E) DNA polymerase I.
G) C) and D)
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A) The same DNA polymerase replicates mitochondrial, chloroplast, and nuclear DNA.
B) There are only two different DNA polymerases that function in the process of replication.
C) Some DNA polymerases have the ability to function in DNA repair mechanisms.
D) All eukaryotic DNA polymerases have 3' 5' exonuclease activity.
E) Leading strand synthesis and lagging strand synthesis are performed by the same type of DNA polymerase.
G) B) and E)
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A) DNA gyrase; making and resealing the break to remove the torque as the DNA unwinds
B) DNA ligase; sealing nicks in the sugar-phosphate backbone of newly synthesized DNA
C) DNA helicase; rewinding and reforming the DNA double helix as the replication terminates
D) DNA polymerase III; elongating a new nucleotide strand from the 3'-OH provided by the primers
E) Initiator protein; binding to replication origin and separating DNA to initiate replication
G) B) and C)
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C
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A) connects Okazaki fragments by sealing nicks in the sugar-phosphate backbone
B) unwinds the double helix by breaking the hydrogen bonding between the two strands at the replication fork
C) reduces the torsional strain that builds up ahead of the replication fork as a result of unwinding
D) binds to oriC and causes a short section of DNA to unwind
E) prevents the formation of secondary structures within single-stranded DNA
G) A) and B)
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A) 7.5 seconds
B) 15 seconds
C) 30 seconds
D) 1 minute
E) 2 minutes
G) B) and C)
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No, Okazaki fragments are not formed on ...View Answer
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A) 0
B) 1/8
C) 1/4
D) 1/3
E) 1/2
G) B) and D)
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A) There would be no effect because ribonucleotides are used in RNA synthesis, not DNA synthesis.
B) DNA synthesis would continue but at a slower rate.
C) There would only be an effect during M phase, not in S phase.
D) DNA synthesis would not be affected because ribonucleotides are only used during the process of transcription.
E) Replication would cease because ribonucleotides are required to initiate DNA synthesis.
G) None of the above
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E
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A) DNA; DNA
B) RNA; RNA
C) DNA; RNA
D) RNA; DNA
E) leading strand; DNA
G) C) and D)
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a. If the 5' to 3' polymerase activity o...View Answer
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A) theta model
B) rolling-circle model
C) linear model
D) eukaryotes
E) bacteria
G) All of the above
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A) connects Okazaki fragments by sealing nicks in the sugar-phosphate backbone
B) unwinds the double helix by breaking the hydrogen bonding between the two strands at the replication fork
C) reduces the torsional strain that builds up ahead of the replication fork as a result of unwinding
D) binds to oriC and causes a short section of DNA to unwind
E) prevents the formation of secondary structures within single-stranded DNA
G) A) and C)
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A) the template strand
B) the energy of pentose sugar
C) 5ʹ end of the growing DNA
D) cleavage of two phosphate groups from the dNTP
E) The reaction does not require an energy source.
G) A) and C)
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The Holliday model and the double-strand...View Answer
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The discrepancy between the number of recombination sites and the number of genetic exchanges can be explained by the occurrence of multiple recombination events at a single site. During meiosis, homologous chromosomes undergo genetic recombination, where segments of DNA are exchanged between maternal and paternal chromosomes. This process creates new combinations of genetic material and contributes to genetic diversity.
The special dye that reveals recombination sites allows for the direct visualization of these events on meiotic chromosomes. However, it is possible for multiple recombination events to occur at the same physical location on a chromosome, resulting in the detection of more recombination sites than the actual number of genetic exchanges.
Additionally, the resolution of the dye may allow for the detection of smaller recombination events that do not result in observable genetic exchanges. These smaller events may not lead to detectable changes in the segregation of genetic markers across the genome, leading to a discrepancy between the number of recombination sites and genetic exchanges.
Overall, the discrepancy between the number of recombination sites and genetic exchanges can be attributed to the complexity of meiotic recombination and the limitations of detection methods. It highlights the intricacies of genetic recombination and the need for comprehensive approaches to studying these processes.
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The discovery of a drug that specificall...View Answer
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Telomerase is an enzyme that plays a sig...View Answer
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A) 7.5 seconds
B) 15 seconds
C) 30 seconds
D) 1 minute
E) 2 minutes
G) A) and D)
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A) telomerase
B) DNA gyrase
C) Tus
D) primase
E) topoisomerase
G) A) and D)
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A) conservative
B) dispersive
C) continuous
D) discontinuous
E) recombinant
G) A) and C)
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